Average Properties - From the Microscopic to the Macroscopic
Calculation of Average Energy
If
we denote the average energy <E> then

Recalling
that b = 1/ kBT(click
here for more details)


The
Ensemble Partition Function
We distinguish here between the partition function
of the ensemble, Q and that of an individual molecule, q. Since Q represents a sum over all states
accessible to the system it can written as

where
the indices i,j,k, represent energy levels of different particles.
The discussion of fermions and bosons in M&S
17-7 does not really matter for the conclusions we reach in this course.
Fermion = particle of half-integer spin (s = 1/2,
3/2 …)
Boson = particle of integer spin (s = 0, 1, 2…)
Regardless of the type of particle the
molecular partition function, q represents the energy levels of one individual
molecule. We can rewrite the above sum
as Q = qiqjqk… or Q = qN for N
particles (M&S 17-6). Note that qi
means a sum over states or energy levels accessible to molecule i and qj
means the same for molecule j.
The molecular partition function
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counts the energy levels accessible to molecule i only. Q counts not only the states of all of the molecules, but all of the possible combinations of occupations of those states. However, if the particles are not distinguishable then we will have counted N! states too many (N! = N(N-1)(N-2)….). This factor is exactly how many times we can swap the indices in Q(N,V,T) and get the same value (again provided that the particles are not distinguishable). If we consider 3 particles we have i,j,k j,i,k, k,i,j k,j,i j,k,i i,k,j or 6 = 3!. This is true for fermions (s=1/2 electrons) and bosons (s=0 nuclei). Thus we write the partition function as

We have seen above that the internal energy of the
system can be calculated using the partition function. In fact, all thermodynamic quantities can be
calculated from molecular properties using the partition function. For an ideal gas of non-interacting
particles only the translational partition function matters. Indeed, our focus will be on the effects of
translation properties and we will prove later that translation alone defines
the properties of an ideal gas. It is
important to mention at this point that molecular vibrational, rotational, and
even electronic states also can contribute to the molecular partition
function. This discussion complements
section 17-8 in M&S.
Molecular energy levels are
e = eatrans + ebvib
+ ecrot + edelec
where
the indices a, b, c, d run over the levels of one particular molecule. I use different indices than M&S to
differentiate the statements made about one individual molecule from those
above concerning the ensemble. We can
write the molecular partition function as

In
chemistry 431 we derive only the translational partition function
explicitly. The others discussed in
section 17-8 of M&S will be discussed in 433.
The translational partition function is the
most important one for statistical thermodynamics. As we have seen, pressure is caused by translational motion,
i.e., momentum exchange with the walls of a container. For this reason it is important to
understand the origin of the translational partition function (M&S
18-1). Translational energy levels are
so closely spaced as that they are essentially a continuous distribution. The quantum mechanical description of the
energy levels is obtained from the quantum mechanical particle in a box. This will be solved in 433 (see M&S 3-5
for more information). Here we present
the result used by M&S in 18-1. The energy levels are

The
box is a cube of length a. The average
quantum numbers will be very large for a typical molecule. This is very different than what we find for
vibration and electronic levels where the quantum numbers are small (i.e. only
one or a few levels are populated).
Many translational levels are populated thermally.
The translational partition function is

The
three summations are identical and so they can be written as the cube of one
summation

The
fact that the energy levels are essentially continuous and that the average
quantum number is very large allows us to rewrite the sum as an integral.

The
sum started at 1 and the integral at 0.
This difference is not important if the average value of n is ca. 109! If we have the substitution a = h2/8ma2kBT we can rewrite the integral as

This
is a Gaussian integral. The solution of
Gaussian integrals is discussed in Math chapter B of M&S and on the review
section of the Website. If we now plug
in for a and recognize that the volume of the box is V = a3 we have
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which
agrees with the kinetic theory of gases and the results derived in M&S
17-3. The justification for the first
step is found in Eqn. 17-20. The second
step follows from the fact that ln(abc) = ln(a) + ln(b) + ln(c). McQuarrie and Simon show you that you can
rewrite the logarithm as a sum and that terms that do not depend on temperature
will vanish.
The
microscopic picture of the translation partition function is derived from the
quantum mechanical box problem. We can
also examine the velocity distribution of molecules and calculate the
translation partition function from that.
We will obtain the same answer, of course. The classical result follows directly from the discussion in
section 25-2 where it is shown that the distribution of molecular speeds follow
a Gaussian distribution.
We have already seen that the average energy can be
calculated using the partition function.
The basic approach is to sum over the probability of a state being
occupied times the value of the property in a given state. In general, for an average property A we can write

A
could be energy or pressure etc. pj is the Boltzmann probability
given by pj = e-bej/Q.
The heat capacity is a coefficient that gives the amount of energy to raise the temperature of a substance by one degree Celsius. The heat capacity can also be described as the temperature derivative of the average energy. The constant volume heat capacity is defined by

The
molar internal energy of a monatomic ideal gas is

The
heat capacity of a monatomic ideal gas is therefore

These derivations come from the kinetic theory of gases and also from the definition of the translational partition function. For a monatomic gas there are three degrees of freedom per atom (these are the translations along the x, y, and z direction). Each of these translations corresponds to ˝RT of energy. For an ideal diatomic gas some of the energy used to heat the gas may also go into rotational and vibrational degrees of freedom. For solids there is no translation or rotation and therefore the entire contribution to the heat capacity comes from vibrations. Given their extended nature the vibrations in solids are much lower in frequency than those of gases. Therefore, while vibrations in typical diatomic gases typically contribute little to the heat capacity, the vibrational contribution to the heat capacity of solids is the largest contribution. This is discussed more in Example 17-3 in M&S. The salient point is that the partition function approaches 1 at zero temperature. Physically, this means that only one state is accessible if the temperature is nearly at absolute zero. As the temperature is increased, there are more levels of the solid accessible by thermal energy and therefore Q increases. This also means that U increases and finally that Cv increases. In the high temperature limit in an ideal solid there are 3N vibrational modes that are accessible giving rise to a contribution to the molar heat capacity of 3R. This result is also known as the law of Dulong and Petit.
Pressure can also be derived from the partition function.

We will show later that pressure is expressed as

The
average pressure is the sum of the probability times the pressure

so
we can write

In
a few steps we can show that the temperature can be expressed in terms of the
partition function. Since the
derivative is with respect to volume, the pressure depends only the
translational partition function. To
begin with we remind you of the definition of the partition function

The derivative of the partition function with respect to volume is

The
average pressure can then be written as

Which
shows that the pressure can be expressed solely terms of the partition
function.

We can use this result to derive the
ideal gas law. For N particles of an
ideal gas where

is
the translational partition function.
The utility of expressing the pressure as a logarithm is clear from the
fact that we can write

We
have used the property of logarithms that ln(AB) = ln(A) + ln(B) and ln(XY)
= Yln(X). Only one term in the lnQ
depends on V. Taking the derivative of
NlnV with respect to V gives

Substituting
this into the above equation for the pressure gives P=NkBT/V
which is the ideal gas law. Recall that
Nk = nR where N is the number of molecules and n is the number of moles. R is the universal gas constant (8.314
J/mol-K) which is nothing more than k multiplied by Avagadro’s number. NAk = R converts the constant
from a “per molecule” to a “per mole” basis.