The Quantum World, Energy and Entropy
Quantum Levels
The Boltzmann Distribution
Statistical Entropy is S = k lnW where W is the weight (number of ways particles can be distributed in a system).
The weight is:

Conservation of energy requires:

Conservation of mass requires:
Using S = k lnW we can reason that the system will tend towards the distribution among the ni that maximizes S.
This condition is satisfied by d( lnW ) = 0.
Additionally conservation of energy and mass can be restated as:

Using the method of LaGrange undetermined multipliers we have:
We can evaluate (¶lnW/¶ni) = (¶lnN!/¶ni) – Sj (¶ln nj!/¶ni) using Stirling's approximation:
lnx! » xlnx – x
Simplification of (¶lnW/¶ni)
First step is to note that lnW = lnN! - Sj ln nj! = NlnN – N - Sj nj ln nj - Sj nj
Since N = Sj nj these two cancel to give lnW = NlnN - Sj nj ln nj


These latter derivatives result from the fact that (
¶ni/¶ni) = 1 and (¶nj/¶ni)=0.Therefore we have:
and we have:

The most probable distribution is:
Now we only need to find the undetermined multipliers a and b.


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This determines
a and defines the Boltzmann distribution.
The Boltzmann distribution is:

It is not immediately obvious why this is so significant. This is because we have not yet defined
b. Looking ahead we will show that b=1/kT and that this distribution represents a thermally equilibrated most probable distribution over all energy levels.
The fraction of molecules in state i is pi:

The molecular partition function q gives an indication of the average number of states that are thermally accessible to a molecule at the temperature of the system.

The Boltzmann distribution can be written:
We can now proceed to write the total energy:

Substituting in ni from above:

Now, note a little trick:

The energy can be expressed as:

Now, to identify
b we can study the energy levels and partition function of translation.Note: The quantum chemical and classical treatments of translation are the same.

where px is the momentum in the x direction etc.
The partition function, q is:
This is a Gaussian integral (in three dimensions). In one dimension this becomes:

In the present case
s = b/2m and therefore making the substitution x = px etc.We have:

To calculate the energy we need the derivative dq/d
b:
The energy then is:
This can be compared to the kinetic theory of gases result:

from which we deduce that:

Statistical Thermodynamics
Note the we have calculated E = U – U(0), which is the internal energy referenced to the value, U(0) at absolute zero (T = 0 K).
We can now calculate the entropy S = k ln W


Now recalling the definition of the Boltzmann distribution lnpi =-
bei – lnq
The entropy is,
or
